Question

2) (3√4,41)² - (-2)³ ; 2=?​

Answer 1

Відповідь:

(3 √4,41)² - (-2)³ = 3² * (√4,41)² - (-8) = 9 * 4,41 + 8 = 39,69 + 8 = 47,69,

Answer 2

Let's break down the expression step by step:

1. $(3\sqrt{4}, 41)^2$: $3\sqrt{4} = 3 \times 2 = 6$ (because $\sqrt{4} = 2$) So, $(3\sqrt{4}, 41)^2 = (6, 41)^2$

   $(6, 41)^2 = (6^2, 41^2)$ $(6^2, 41^2) = (36, 1681)$

2. $(-2)^3$: $(-2)^3 = -2 \times -2 \times -2 = -8$

Now, let's proceed with the final calculation:

$(36, 1681) - (-8)$ $= 1681 + 8$ (because subtracting a negative number is the same as adding its positive counterpart) $= 1689$

Now, we need to find $2 = ?$ such that $2 \times ? = 1689$:

$? = \frac{1689}{2}$ $? = 844.5$