Question

2/3(3x+9)=-4(x-1)-1.​

Answer 1

Ответ:

$\frac{2}{3}(3x+9)=-4(x-1)-1\\ \frac{2(3x+9)}{3}= -4(x-1)-1\\\frac{6x+18}{3}=-4x+4-1\\\frac{3(2x+6)}{3}=-4x+3\\2x+6=-4x+3\\6x=-3\\x=-\frac{3}{6}=-\frac{1}{2}=-0.5$

Answer 2

To solve the equation 2/3(3x+9) = -4(x-1) - 1, follow these steps:

1. Distribute the coefficients on both sides of the equation to eliminate parentheses:

   (2/3) * (3x+9) = -4(x-1) - 1

   (2/3) * 3x + (2/3) * 9 = -4x + 4 - 1

2. Simplify each side:

   2x + 6 = -4x + 3

3. Move the terms involving x to one side of the equation and the constants to the other side:

   2x + 4x = 3 - 6

   6x = -3

4. Divide both sides by 6 to solve for x:

   (6x)/6 = (-3)/6

   x = -1/2

So, the solution to the equation is x = -1/2.