Question

(x-y-5=0 44x + y - 10 = 0​

Answer 1

{х-у-5=0
{44х+у-10=0

{х-у-5=0
{у=-44х+10

х-(-44х+10)-5=0
х+44х-10-5=0
45х-15=0
45х=15
х=1/3
у=-44*1/3+10
у=-44/3+10
у=-14/3
у=-4 2/3
(х;у)=(1/3;-4 2/3)

Answer 2

It seems like you have provided two linear equations:

1. x - y - 5 = 0
2. 44x + y - 10 = 0

You can solve this system of linear equations using various methods such as substitution, elimination, or matrices. Let's solve it using the elimination method:

First, let's add the two equations together to eliminate the variable "y":

(x - y - 5) + (44x + y - 10) = 0

This simplifies to:

45x - 15 = 0

Now, add 15 to both sides of the equation to isolate "x":

45x = 15

Next, divide both sides by 45 to solve for "x":

x = 15 / 45 x = 1/3

Now that we have found the value of "x," we can substitute it into one of the original equations to find the value of "y." Let's use the first equation:

x - y - 5 = 0 (1/3) - y - 5 = 0

Now, solve for "y":

(1/3) - 5 = y

y = (1/3) - 5 y = -14/3

So, the solution to the system of equations is:

x = 1/3 y = -14/3