Question

(5x-4)(8x+1,6)=0(10-2,5x)(3,2x-0,8)=0

Answer 1

Відповідь:

Покрокове пояснення:

Answer 2

It seems like you have two equations, each set equal to zero. Let's solve them separately:

Equation 1: (5x - 4)(8x + 1.6) = 0

To find the values of x that satisfy this equation, we can set each factor equal to zero:

1. 5x - 4 = 0 5x = 4 x = 4/5

2. 8x + 1.6 = 0 8x = -1.6 x = -1.6/8 x = -0.2

So, for the first equation, x = 4/5 or x = -0.2.

Now, let's solve the second equation:

Equation 2: (10 - 2.5x)(3.2x - 0.8) = 0

Again, set each factor equal to zero:

1. 10 - 2.5x = 0 -2.5x = -10 x = -10 / -2.5 x = 4

2. 3.2x - 0.8 = 0 3.2x = 0.8 x = 0.8 / 3.2 x = 0.2

For the second equation, x = 4 or x = 0.2.

So, the solutions to the equations are: For Equation 1: x = 4/5 or x = -0.2 For Equation 2: x = 4 or x = 0.2