Question

1. 3x+10=-2x-10 2. x-2(x+3)=3x+2

Answer 1

Ответ:

Ответ ниже

Пошаговое объяснение:

1) 3x+10=2x-10

3x+10-10=2x-10-10

2) x-2(x+3)=3x+2

x-6=3x+2

Answer 2

Ответ:

Пошаговое объяснение:

1. 3х+10=-2х-10

переносим х в левую часть, а числа в правую

3х+2х=-10+10

5х=

х=бесконечное кол.во решений

2. х-2(х+3)=3х+2

х-2х-6=3х+2

переносим:

х-2х-3х=6+2

-4х=8

х=-2

Answer 3

Let's solve both of these equations step by step:

1. $3x + 10 = -2x - 10$

To solve this equation, we want to isolate the variable $x$ on one side.

First, let's get all the terms involving $x$ on one side by adding $2x$ to both sides of the equation:

$3x + 10 + 2x = -2x - 10 + 2x$

Now, simplify both sides:

$5x + 10 = -10$

Next, subtract 10 from both sides to isolate $5x$:

$5x + 10 - 10 = -10 - 10$

$5x = -20$

Now, divide both sides by 5 to solve for $x$:

$\frac{5x}{5} = \frac{-20}{5}$

$x = -4$

So, the solution to the first equation is $x = -4$.

2. $x - 2(x + 3) = 3x + 2$

Again, we'll start by simplifying the equation:

$x - 2x - 6 = 3x + 2$

Now, combine like terms on both sides:

$-x - 6 = 3x + 2$

Next, add $x$ to both sides to move the terms involving $x$ to one side:

$-x + x - 6 = 3x + x + 2$

Simplify:

$-6 = 4x + 2$

Subtract 2 from both sides:

$-6 - 2 = 4x + 2 - 2$

$-8 = 4x$

Now, divide both sides by 4 to solve for $x$:

$\frac{-8}{4} = \frac{4x}{4}$

$-2 = x$

So, the solution to the second equation is $x = -2$.

Therefore, the solutions to the two equations are:

1. $x = -4$
2. $x = -2$