Question

1)29x - 15x + 16 = 100 2)11y + 32y - 127 3)15z + 8z - 59 = 102

Answer 1

1) 29х-15х+16=100
14х=100-16
14х=84
х=84:14
х=6
2)11у+32у-127=43у-127
3)15z+8z-59=102
23z=102+59
23z=161
z=161:23
z=7

Answer 2

1) 14х=84
х=6
2) 43у=127 (возможна ошибка в твоём условии)
у=3
3) 23z=161
z=7

Answer 3

It looks like you have three equations with variables x, y, and z. Let's solve them one by one.

1. 29x - 15x + 16 = 100

Combine like terms:

14x + 16 = 100

Subtract 16 from both sides:

14x = 100 - 16 14x = 84

Now, divide both sides by 14 to isolate x:

x = 84 / 14 x = 6

So, the solution to the first equation is x = 6.

2. 11y + 32y - 127

Combine like terms:

43y - 127

3. 15z + 8z - 59 = 102

Combine like terms:

23z - 59 = 102

Add 59 to both sides:

23z = 102 + 59 23z = 161

Now, divide both sides by 23 to isolate z:

z = 161 / 23 z = 7

So, the solution to the third equation is z = 7.

In summary:

1. x = 6
2. 43y - 127
3. z = 7