Question

3(1,2x+7y)+3x*0,1при1,y=0,1

Answer 1

3(1,2x+7y)+3x*0,1=3,6x+21y+0,3x=3,9x+21y=3,9*1+21*0,1=3,9+2,1=6
ответ: 6

Answer 2

To evaluate the given expression 3(1, 2x + 7y) + 3x * 0.1 when x = 1 and y = 0.1, follow these steps:

1. Replace x with 1 and y with 0.1 in the expression: 3(1, 2(1) + 7(0.1)) + 3(1) * 0.1

2. Perform the calculations inside the parentheses: 3(1, 2 + 0.7) + 3(0.1)

3. Simplify the calculations further: 3(1, 2.7) + 0.3

4. Multiply 3 by each term inside the parentheses: 3 * 1 + 3 * 2.7 + 0.3

5. Calculate the results of the multiplications: 3 + 8.1 + 0.3

6. Add up the results: 11.4

So, when x = 1 and y = 0.1, the value of the expression 3(1, 2x + 7y) + 3x * 0.1 is 11.4.