Question

506+m=2003; k-357=218; 601-x=408; 69+(87-h)=103; x+7=11-x

Answer 1

506+m=2003           
m=203-506
m= -303

k-357=218
k=218+357
k=575

601-x=408
-x=408-601
-x= -193
x=193

69+(87-h)=103
69+87-h=103
156-h=103
-h=103-156
-h= -53
h=53

x+7=11-x
x+x=11-7
2x=4
x=2

Answer 2

1) 506+m=2003
m=2003-506
m=1497
Ответ:1497

2)k-357=218
k=357+218
k=575
Ответ:575

3)601-x=408
x=601-408
x=193
Ответ:193

4)69+(87-h)=103
h=103-69
h=34
ПРОВЕРКА:
69+(87-34)=103
Ответ:34

5)x+7=11-x
x2=11-7=4
x+7=11-4=7
x1=7-7=0
ПРОВЕРКА:
0+7=7
ОТВЕТ:0

Answer 3

It looks like you've provided a set of equations. Let's solve each one step by step:

1. 506 + m = 2003 Subtract 506 from both sides: m = 2003 - 506 = 1497

2. k - 357 = 218 Add 357 to both sides: k = 218 + 357 = 575

3. 601 - x = 408 Subtract 601 from both sides: -x = 408 - 601 = -193 Multiply both sides by -1: x = 193

4. 69 + (87 - h) = 103 Simplify the parentheses: 69 + 87 - h = 103 Combine the constants: 156 - h = 103 Subtract 156 from both sides: -h = 103 - 156 = -53 Multiply both sides by -1: h = 53

5. x + 7 = 11 - x Add x to both sides: 2x + 7 = 11 Subtract 7 from both sides: 2x = 11 - 7 = 4 Divide both sides by 2: x = 4 / 2 = 2

So, the solutions for the variables are:

• m = 1497
• k = 575
• x = 193
• h = 53