
7м 205 мм×62 =? 2 кг 328 г×83 =? 9см5мм ×67=? 9смкв5ммкв ×67=? 120 м84см ÷6=? 399м.кв 75 см.кв ÷25=?


Ответы на вопрос

9см5мм*67=95*67=6365
9см кв5мм кв*67=905*67=60635
120м 84см:6=12084:6=2014
399м кв75см кв:25=3990075:25=159603
7м 205мм*62=7205*62=446710



To solve the given mathematical expressions, let's perform the calculations step by step:
7м 205 мм × 62: First, convert 7 meters to millimeters: 7 meters = 7 * 1000 mm = 7000 mm Now, add the additional 205 mm: 7000 mm + 205 mm = 7205 mm Finally, multiply by 62: 7205 mm × 62 = 446,710 mm or 446.71 meters (rounded to 2 decimal places).
2 кг 328 г × 83: First, convert 2 kilograms to grams: 2 kilograms = 2 * 1000 g = 2000 g Now, add the additional 328 grams: 2000 g + 328 g = 2328 g Finally, multiply by 83: 2328 g × 83 = 193,224 g or 193.224 kilograms (rounded to 3 decimal places).
9см 5мм × 67: First, convert 5 millimeters to centimeters: 5 mm = 5 ÷ 10 cm = 0.5 cm Now, add the additional 9 centimeters: 9 cm + 0.5 cm = 9.5 cm Finally, multiply by 67: 9.5 cm × 67 = 636.5 cm or 6.365 meters (rounded to 3 decimal places).
9см² 5мм² × 67: Since the expressions have "²" symbols, it indicates that they are areas and not regular multiplication.
For 9 cm² 5 mm² × 67, we'll calculate the area: First, convert 5 mm to cm: 5 mm = 5 ÷ 10 cm = 0.5 cm Now, add the additional 9 cm² + 0.5 cm² = 9.5 cm² Finally, multiply by 67: 9.5 cm² × 67 = 636.5 cm².
120 м 84 см ÷ 6: First, convert 120 meters to centimeters: 120 meters = 120 * 100 cm = 12,000 cm Now, add the additional 84 cm: 12,000 cm + 84 cm = 12,084 cm Finally, divide by 6: 12,084 cm ÷ 6 = 2,014 cm or 20.14 meters (rounded to 2 decimal places).
399 м² 75 см² ÷ 25: Since the expressions have "²" symbols, it indicates that they are areas and not regular division.
For 399 m² 75 cm² ÷ 25, we'll calculate the area: First, convert 75 cm² to m²: 75 cm² = 75 ÷ 10,000 m² = 0.0075 m² Now, add the additional 399 m² + 0.0075 m² = 399.0075 m² Finally, divide by 25: 399.0075 m² ÷ 25 = 15.9603 m² (rounded to 4 decimal places).
Note: In all calculations, I have rounded the results to the appropriate number of decimal places.


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