Question

Ришите плиз 3(2y-1)+6(3y-4)=83+5(y-3)

Answer 1

3(2у-1)+6(3у-4)=83+5(у-3)
6y-3+18y-24=83+5y-15
24y-27=68+5y
24y-5y=68+27
19y=95
y=95:19
y=5

Answer 2

6y-3+18y-24=83+5y-15
6y+18y-5y=83-15+3+24
19y=95
y=95÷19
y=5

Answer 3

Sure, I'd be happy to help you solve the equation!

Let's start by simplifying both sides of the equation step by step:

1. Distribute the terms on the left side: 3(2y - 1) + 6(3y - 4) = 83 + 5(y - 3)

Expand the terms: 6y - 3 + 18y - 24 = 83 + 5y - 15

2. Combine like terms on both sides: (6y + 18y) + (-3 - 24) = (5y) + (83 - 15)

24y - 27 = 5y + 68

3. Move all y terms to one side and constant terms to the other side: 24y - 5y = 68 + 27

19y = 95

4. Solve for y by dividing both sides by 19: y = 95 / 19

y = 5

So, the value of y that satisfies the equation is y = 5.