
(3-7х)у+7у(х+9)=264 Х(4-у)=у(8-х)-34


Ответы на вопрос

3у-7ху+7ху+63у=264
66у=264
у=264:66
у=4
4х-ху-8у+ху=-34
4х-8у=-34
4х-8*4=-34 4х=-34+32
у=4
х=-1/2







To solve the system of equations:
- (3 - 7х)у + 7у(х + 9) = 264
- х(4 - у) = у(8 - х) - 34
Let's start with the first equation:
- (3 - 7х)у + 7у(х + 9) = 264
First, let's expand the terms:
3у - 7ху + 7xy + 63у = 264
Now, combine like terms:
10у + 7xy - 7ху = 264
Now, let's move all terms to one side to set the equation to zero:
10у + 7xy - 7ху - 264 = 0
Next, let's work on the second equation:
- х(4 - у) = у(8 - х) - 34
Expand the terms:
4х - ху = 8у - ху - 34
Now, let's move all terms to one side to set the equation to zero:
4х - ху - 8у + ху + 34 = 0
Now, we have two equations:
- 10у + 7xy - 7ху - 264 = 0
- 4х - ху - 8у + ху + 34 = 0
Now, we can try to solve for у in terms of х from the second equation:
4х - ху - 8у + ху + 34 = 0
Combine like terms:
4х - 8у + 34 = 0
Subtract 4х from both sides:
-8у + 34 = -4х
Now, isolate у by dividing both sides by -8:
у = (-4х - 34) / -8
у = (4х + 34) / 8
у = (х + 8.5)
Now that we have у in terms of х, let's substitute this expression back into the first equation:
10у + 7xy - 7ху - 264 = 0
10(х + 8.5) + 7х(х + 8.5) - 7х(х + 8.5) - 264 = 0
Simplify:
10х + 85 + 7х^2 + 59.5х - 59.5х - 264 = 0
Combine like terms:
7х^2 + 10х - 179 = 0
Now we have a quadratic equation in terms of х. We can solve this equation using the quadratic formula:
The quadratic formula is given by:
х = (-b ± √(b^2 - 4ac)) / 2a
In our case, a = 7, b = 10, and c = -179:
х = (-(10) ± √((10)^2 - 4(7)(-179))) / 2(7)
х = (-10 ± √(100 + 5024)) / 14
х = (-10 ± √(5124)) / 14
Now, calculate the two possible values of х:
- х = (-10 + √(5124)) / 14 ≈ 5.65
- х = (-10 - √(5124)) / 14 ≈ -5.36
Now that we have the values of х, we can find the corresponding values of у:
- у = (х + 8.5) ≈ (5.65 + 8.5) ≈ 14.15
- у = (х + 8.5) ≈ (-5.36 + 8.5) ≈ 3.14
So, the solutions to the system of equations are approximately:
- х ≈ 5.65, у ≈ 14.15
- х ≈ -5.36, у ≈ 3.14


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