Question

9^3+x+3^2(x+1)=738*1/81

Answer 1

$9^{3+x} + 3^{2*(x+1)} =738* \frac{1}{81}$
$(3^{2} ) ^{3+x} + 3^{2x+2} =738* \frac{1}{81}$
$3^{2x+6} + 3^{2x+2} =738* \frac{1}{81}$
$3^{2x+2}*( 3^{4}+1 )=738* \frac{1}{81}$
$3^{2x+2}*(81+1)=738* \frac{1}{81} | :82$
$3^{2x+2}= \frac{1}{9} 3^{2x+2}= 3^{-2}$

2x+2=-2
2x= - 4


x= - 2

Answer 2

729+x+9(x+1)=738/81
729+x+9x+9=82/9
738+10x=82/9
10x= -6560/9
X= -656/9

Answer 3

To solve the equation, let's start by simplifying the right-hand side:

738 * 1/81 = 738 / 81

Now, we can rewrite the equation as follows:

9^3 + x + 3^2(x + 1) = 738 / 81

Next, calculate the values of 9^3 and 3^2:

9^3 = 729 3^2 = 9

Now, substitute these values back into the equation:

729 + x + 9(x + 1) = 738 / 81

Now, distribute the 9 on the left side of the equation:

729 + x + 9x + 9 = 738 / 81

Combine like terms:

10x + 738 = 738 / 81

Now, isolate the variable x on one side of the equation:

10x = 738 / 81 - 738

Next, convert the constant on the right side to have the same denominator as 81:

10x = 738 / 81 - 738 * 81 / 81

Now, perform the subtraction on the right side:

10x = (738 - 738 * 81) / 81

Now, simplify the expression on the right side:

10x = (738 - 59778) / 81

10x = -59040 / 81

Finally, divide both sides by 10 to solve for x:

x = (-59040 / 81) / 10

x = -5904 / 81

x ≈ -72.89

So, the approximate value of x is -72.89.