Question

√x^2-7x-8всё уравнение под корнем

Answer 1

X^2-7x=8
x^2-7x-8=0
D=(-7)^2-4*1*(-8)=49+32=81
x1=7-9/2=-1
x2=7+9/2=8

Answer 2

To solve the equation √(x^2 - 7x - 8) = 0, you need to isolate the square root term and then square both sides to eliminate the square root. Here's how you can do it step-by-step:

Step 1: Isolate the square root term. √(x^2 - 7x - 8) = 0

Step 2: Square both sides. (√(x^2 - 7x - 8))^2 = 0^2

Step 3: Simplify the left side. (x^2 - 7x - 8) = 0

Step 4: Now you have a quadratic equation. To solve it, factor or use the quadratic formula.

The quadratic equation x^2 - 7x - 8 = 0 can be factored as follows: (x - 8)(x + 1) = 0

Step 5: Set each factor to zero and solve for x. x - 8 = 0 --> x = 8 x + 1 = 0 --> x = -1

So, the solutions to the original equation √(x^2 - 7x - 8) = 0 are x = 8 and x = -1.