Question

Решите уравнение:(7x-2)(7x+1,4)=0

Answer 1

(7x-2)(7x+1,4)=0

7x-2=0     7x+1,4=0
7x=2        7x= -1,4
x1=2/7     x= -1,4/7
                x2= -0,2

Answer 2

(7x-2)(7x+1,4)=0
7x - 2 = 0 или 7x + 1,4 = 0
7x = 2             7x = -1,4
x = 2 : 7          x = -1,4 : 7
x = 2/7 или    x = -0,2

Answer 3

To solve the equation $(7x-2)(7x+1.4) = 0$, we need to find the values of $x$ that make the expression equal to zero.

For this equation to be true, one of the factors must be equal to zero, as the product of two numbers is zero if and only if at least one of them is zero.

So, we set each factor to zero and solve for $x$:

1. $7x - 2 = 0$ Adding 2 to both sides: $7x = 2$ Dividing by 7: $x = \frac{2}{7}$

2. $7x + 1.4 = 0$ Subtracting 1.4 from both sides: $7x = -1.4$ Dividing by 7: $x = -\frac{1.4}{7}$ $x = -0.2$

So, the solutions to the equation are $x = \frac{2}{7}$ and $x = -0.2$.