Question

A)4x^2-9=0 b)y^2-10y-24=0 C)5x^-8x+3=0

Answer 1

А) 4х^2=9
х=-3/2
х1=-3/3 , х2=3/2

b) y^2+2y-12y-24=0
y*(y+2)-12(y+2)=0
(y+2)*(y-12)=0
y+2=0
y-12=0
y=-2
y=12
y1=-2
y2=12

c) 5x^-3x-5x+3=0
x*(5x-3) -(5x-3)=0
(5x-3)*(x-1)=0
5x-3=0
x-1=0
x=3/5
x=1
x1=3/5
x2=1


Знак деления /

Answer 2

Let's solve each of the given quadratic equations:

A) 4x^2 - 9 = 0

To solve this quadratic equation, we can use the difference of squares factorization:

4x^2 - 9 = (2x)^2 - 3^2 = (2x + 3)(2x - 3) = 0

Now, set each factor to zero and solve for x:

2x + 3 = 0 2x = -3 x = -3/2

2x - 3 = 0 2x = 3 x = 3/2

So, the solutions to the equation are x = -3/2 and x = 3/2.

B) y^2 - 10y - 24 = 0

To solve this quadratic equation, we can factor it:

y^2 - 10y - 24 = (y - 12)(y + 2) = 0

Now, set each factor to zero and solve for y:

y - 12 = 0 y = 12

y + 2 = 0 y = -2

So, the solutions to the equation are y = 12 and y = -2.

C) 5x^2 - 8x + 3 = 0

To solve this quadratic equation, we can factor it:

5x^2 - 8x + 3 = (5x - 3)(x - 1) = 0

Now, set each factor to zero and solve for x:

5x - 3 = 0 5x = 3 x = 3/5

x - 1 = 0 x = 1

So, the solutions to the equation are x = 3/5 and x = 1.