Question

㏒3(внизу) 18

Answer 1

$\frac{log_318}{2+log_32}=\frac{log_318}{log_33^2+log_32}=\frac{log_318}{log_39+log_32}=\frac{log_318}{log_3(9\cdot 2)}=\frac{log_318}{log_318}=1$

Answer 2

It looks like the expression you provided is unclear. It seems to be a logarithm notation with a base of 3 and a value of 18, but the "(внизу)" part is not well-defined. It would be helpful if you could clarify or rephrase your question so that I can better assist you.

In logarithm notation, "log base b of a" is written as log_b(a), where 'b' is the base and 'a' is the value. For example, log_3(18) would represent the logarithm base 3 of 18. If you have a specific question or want to solve a particular logarithmic equation, please provide more information, and I'll be glad to help.