Question

9 ^4х +5 =729 Решение нужно!!!!

Answer 1

Скорее всего имелось ввиду уравнение 9^(4x+5)=729, тогда:

Представляем уравнение в виде: 9^(4x+5)=9^3

Откуда имеем: 4x+5=3

Переносим 5 в правую часть: 4x=3-5

Cчитаем разность: 4x= -2

Делим обе части на 4: x=-0,5

Ответ: -0,5

Answer 2

To solve the equation 9^(4x) + 5 = 729, we'll follow these steps:

Step 1: Subtract 5 from both sides of the equation to isolate the term with the exponent. Step 2: Divide both sides by 9 to remove the exponent. Step 3: Solve for x.

Let's go through it step by step:

Step 1: 9^(4x) + 5 - 5 = 729 - 5 9^(4x) = 724

Step 2: Divide both sides by 9: (9^(4x))^(1/4) = 724^(1/4) 9^x = 724^(1/4)

Step 3: Now, we can solve for x by taking the logarithm of both sides (with any base, but let's use the common logarithm base 10):

x * log(9) = log(724^(1/4))

x = log(724^(1/4)) / log(9)

Using a calculator:

x ≈ 0.3333

So, the solution to the equation is approximately x = 0.3333.