Question

{ 3х 2у =13 { х-у=1 решите уравнение

Answer 1

{3x*2y=13
{x=1+y
1)3(1+y)*2y=13
(3+3y)*2y=13
6y+6y^2-13=0
Д1=9+6*13=87
x1;2=-3+/-корень из 87/3
$\sqrt{?}$

Answer 2

To solve the system of equations, we can use either the substitution method or the elimination method. Let's use the elimination method:

Given the system of equations:

1. 3x + 2y = 13
2. x - y = 1

Step 1: Multiply the second equation by 2 to make the coefficients of y in both equations the same:

2 * (x - y) = 2 * 1 2x - 2y = 2

The system now looks like:

1. 3x + 2y = 13
2. 2x - 2y = 2

Step 2: Add the two equations together to eliminate the y variable:

(3x + 2y) + (2x - 2y) = 13 + 2 5x = 15

Step 3: Solve for x:

x = 15 / 5 x = 3

Step 4: Substitute the value of x back into one of the original equations to solve for y. Let's use equation 2:

x - y = 1 3 - y = 1

Step 5: Solve for y:

y = 3 - 1 y = 2

So, the solution to the system of equations is x = 3 and y = 2.