Question

3x+2-2*=-

Answer 1

$3x+2-2\sqrt{x+3} \sqrt{2x-1}=x+3-2\sqrt{x+3} \sqrt{2x-1}+2x-1=(\sqrt{x+3})^{2}-2\sqrt{x+3} \sqrt{2x-1}+(\sqrt{2x-1})^{2}=(\sqrt{x+3}- \sqrt{2x-1})^{2}\\ y=\sqrt{x+3}- \sqrt{2x-1}\\\\y^{2}=y\\y_{1}=0, y_{2}=1\\y_{1})\\\sqrt{x+3}-\sqrt{2x-1}=0\\\sqrt{x+3}=\sqrt{2x-1}\\x+3=2x-1\\x_{1}=4\\y_{2})\\y_{2}^{2}=3x+2-2\sqrt{x+3} \sqrt{2x-1}=1\\2\sqrt{x+3} \sqrt{2x-1}=3x+1\\4(x+3)(2x-1)=(3x+1)^{2}\\8x^{2}+20x-12=9x^{2}+6x+1\\x^{2}-14x+13=0\\x_{2}=1, x_{3}=13$

Все три полученные ответа входят в ОДЗ ( x≥0.5)

Ответ: х∈{1; 4; 13}

Answer 2

It seems like there is a typo or missing information in the equation you provided. The equation is incomplete as there is no expression on the right side of the equal sign. An equation should have an expression on both sides of the equal sign.

If you could provide the full and correct equation, I'd be happy to help you solve it or provide any assistance you need!