Question

11y-(3y+12)=40 решить уравнение

Answer 1

11y-(3y+12)=40
11y-3y-12=40
8y=52
y=
$6\frac{1}{2}$

Answer 2

11у-(3у+12)=40
11у-3у-12=40
8у=40+12
8у=52
у=52:8
у=6,5

Answer 3

To solve the equation, follow these steps:

1. Distribute the negative sign across the terms inside the parentheses.
2. Combine like terms on both sides of the equation.
3. Isolate the variable (y) on one side of the equation.
4. Solve for y.

Let's go through each step in detail:

1. Distribute the negative sign:

11y - 3y - 12 = 40

2. Combine like terms:

(11y - 3y) - 12 = 40

Now, simplify the terms inside the parentheses:

8y - 12 = 40

3. Isolate the variable:

Add 12 to both sides to move the constant term to the other side:

8y = 40 + 12

8y = 52

4. Solve for y:

To find the value of y, divide both sides by 8:

y = 52 / 8

y = 6.5

So, the solution to the equation is:

y = 6.5