Question

2y(в квадрате) + 5y-3=0

Answer 1

Пошаговое объяснение:

2у² + 5у - 3 = 0,

Д = 5² - 4*2*(-3) = 25 + 24 = 49,

у1 = (-5 + 7) / 2*2 = 2/4 = 1/2   (или  0,5),

у2 = (-5 - 7) / 2*2 = -12/4 = -3  

Answer 2

2у²+5у-3=0
2y²+5y=0+3
2y²+5y=3

Answer 3

To solve the quadratic equation 2y^2 + 5y - 3 = 0, we can use the quadratic formula:

The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In your equation, a = 2, b = 5, and c = -3. Now, let's plug these values into the quadratic formula and find the solutions for y:

y = (-5 ± √(5^2 - 4 * 2 * (-3))) / 2 * 2 y = (-5 ± √(25 + 24)) / 4 y = (-5 ± √49) / 4 y = (-5 ± 7) / 4

Now, we have two possible solutions for y:

1. y = (-5 + 7) / 4 y = 2 / 4 y = 0.5

2. y = (-5 - 7) / 4 y = -12 / 4 y = -3

So, the solutions for the equation 2y^2 + 5y - 3 = 0 are y = 0.5 and y = -3.