
/2x-3/=4 /2x+30/=48 /5x+6/=7 /9-3x/=6


Ответы на вопрос




To solve each absolute value equation, we need to consider both the positive and negative values of the expression within the absolute value bars. Let's solve each equation one by one:
- |2x - 3| = 4
To solve for x, we'll set up two cases:
Case 1: 2x - 3 = 4 Add 3 to both sides: 2x = 4 + 3 2x = 7 Divide by 2: x = 7/2
Case 2: -(2x - 3) = 4 Remove the negative sign: -2x + 3 = 4 Subtract 3 from both sides: -2x = 4 - 3 -2x = 1 Divide by -2: x = -1/2
So, the solutions for the equation |2x - 3| = 4 are x = 7/2 and x = -1/2.
- |2x + 30| = 48
Again, set up two cases:
Case 1: 2x + 30 = 48 Subtract 30 from both sides: 2x = 48 - 30 2x = 18 Divide by 2: x = 18/2 x = 9
Case 2: -(2x + 30) = 48 Remove the negative sign: -2x - 30 = 48 Add 30 to both sides: -2x = 48 + 30 -2x = 78 Divide by -2: x = 78/-2 x = -39
The solutions for the equation |2x + 30| = 48 are x = 9 and x = -39.
- |5x + 6| = 7
Two cases:
Case 1: 5x + 6 = 7 Subtract 6 from both sides: 5x = 7 - 6 5x = 1 Divide by 5: x = 1/5
Case 2: -(5x + 6) = 7 Remove the negative sign: -5x - 6 = 7 Add 6 to both sides: -5x = 7 + 6 -5x = 13 Divide by -5: x = 13/-5
The solutions for the equation |5x + 6| = 7 are x = 1/5 and x = -13/5.
- |9 - 3x| = 6
Two cases:
Case 1: 9 - 3x = 6 Subtract 9 from both sides: -3x = 6 - 9 -3x = -3 Divide by -3: x = -3/-3 x = 1
Case 2: -(9 - 3x) = 6 Remove the negative sign: -(-3x + 9) = 6 Distribute the negative sign: 3x - 9 = 6 Add 9 to both sides: 3x = 6 + 9 3x = 15 Divide by 3: x = 15/3 x = 5
The solutions for the equation |9 - 3x| = 6 are x = 1 and x = 5.
So, the solutions for the given absolute value equations are:
x = 7/2 and x = -1/2 (for |2x - 3| = 4) x = 9 and x = -39 (for |2x + 30| = 48) x = 1/5 and x = -13/5 (for |5x + 6| = 7) x = 1 and x = 5 (for |9 - 3x| = 6)


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