Question

7.12х^2+8х+1=0 8.3х^2+5х-8=0

Answer 1

Вот,надеюсь все понятно

Answer 2

To solve the quadratic equations, we can use the quadratic formula, which is given by:

For a quadratic equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / 2a

Let's solve the given quadratic equations:

1. 7.12x^2 + 8x + 1 = 0 a = 7.12 b = 8 c = 1

x = (-8 ± √(8^2 - 4 * 7.12 * 1)) / 2 * 7.12 x = (-8 ± √(64 - 28.48)) / 14.24 x = (-8 ± √35.52) / 14.24 x = (-8 ± 5.96) / 14.24

So the solutions for the first equation are: x₁ = (-8 + 5.96) / 14.24 ≈ 0.108 x₂ = (-8 - 5.96) / 14.24 ≈ -0.674

2. 8.3x^2 + 5x - 8 = 0 a = 8.3 b = 5 c = -8

x = (-5 ± √(5^2 - 4 * 8.3 * -8)) / 2 * 8.3 x = (-5 ± √(25 + 265.6)) / 16.6 x = (-5 ± √290.6) / 16.6

Unfortunately, the roots of this equation contain an imaginary component (√290.6 is not a real number), which means that there are no real solutions to this quadratic equation. The solutions involve complex numbers.

So the solutions for the second equation are: x₁ = (-5 + √290.6) / 16.6 (complex number) x₂ = (-5 - √290.6) / 16.6 (complex number)

The second equation does not have real solutions, only complex ones.