Question

Решение уравнения (5х+2)(-х-6)=0

Answer 1

Раскроем скобки:

-5x^2-30x-2x-12=0

-5x^2-32x-12=0 |*-1

5x^2+32x+12=0

D = B^2-4AC = 1024 - 240 = 784

$\sqrt{D}$ = $\sqrt{784}$ = +- 28

x1=(-32+28):10 = -4/10 = -0,4

x2=(-32-28):10 = -60/10 = -6

Answer 2

To solve the equation $(5x + 2)(-x - 6) = 0$, we can use the zero product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero. So, to find the solutions, we set each factor equal to zero and solve for $x$:

1. $5x + 2 = 0$: Subtract 2 from both sides: $5x = -2$

Divide both sides by 5: $x = -\frac{2}{5}$

2. $-x - 6 = 0$: Add 6 to both sides: $-x = 6$

Multiply both sides by -1 to isolate x: $x = -6$

The two solutions to the equation are $x = -\frac{2}{5}$ and $x = -6$.