Question

Сократить дробь 10ac+4a² ————— 20c+8a

Answer 1

Вот и все
вроде так, если я правильно поняла

Answer 2

10ac+4a2/20c+8a=2a*(5c+2a)/4(5c+2a)=a/2

5с+2а сокращаются

Сокращение так же

10ac+4a2=2a*(5c+2a)

20c+8a=4(5c+2a)

Answer 3

To simplify the given fraction, we can start by factoring out common terms from both the numerator and the denominator:

Numerator: 10ac + 4a² Common factor: 2a Numerator after factoring: 2a(5c + 2a)

Denominator: 20c + 8a Common factor: 4 Denominator after factoring: 4(5c + 2a)

Now, the fraction becomes:

(2a(5c + 2a)) / (4(5c + 2a))

Next, we can cancel out the common factor of (5c + 2a) from the numerator and the denominator:

(2a * 1) / (4 * 1)

Finally, we have the simplified fraction:

2a / 4

To further simplify, we can divide both the numerator and the denominator by 2:

a / 2

So, the simplified fraction is a/2.