Question

43x+19x=6260y-3y=153907m+m-12=28

Answer 1

Ответ:

Пошаговое объяснение:

43x+19x=62

62х=62

х=62:62

х=1

60y-3y=15390

57х=15390

х=15390:57

х=270

7m+m-12=28

8м=28+12

8м=40

м=40:8

м=5

Answer 2

It appears that you have presented a system of three equations involving three variables (x, y, and m). To solve this system, we need to find the values of x, y, and m that satisfy all three equations simultaneously.

Let's solve each equation step-by-step:

1. 43x + 19x = 6260y - 3y Combine like terms on both sides of the equation: 62x = 6257y

2. 62x = 6257y To simplify the equation, we can divide both sides by their greatest common divisor, which is 1 in this case: 62x = 6257y

3. 6260y - 3y = 153907 Combine like terms on the left side of the equation: 6257y = 153907

4. 6257y = 153907 Now, to solve for y, divide both sides by 6257: y = 153907 / 6257 y ≈ 24.59

Now that we have the value of y, let's proceed to find x:

62x = 6257y Substitute the value of y into the equation: 62x = 6257 * 24.59 62x ≈ 153907

To solve for x, divide both sides by 62: x ≈ 153907 / 62 x ≈ 2480.5

Now, let's find the value of m:

m + m - 12 = 28 Combine like terms on the left side of the equation: 2m - 12 = 28

Add 12 to both sides: 2m = 28 + 12 2m = 40

To solve for m, divide both sides by 2: m = 40 / 2 m = 20

So, the solution to the system of equations is: x ≈ 2480.5 y ≈ 24.59 m = 20