
Sinx/8=-1 срочно!!!!!


Ответы на вопрос

x2= п-8arcsin(-1)+2пn
x1=-4п+2пn
x2=5п+2пn



To solve the equation sin(x)/8 = -1, we need to isolate the variable x. Here's how you can do it step-by-step:
Multiply both sides of the equation by 8 to eliminate the fraction: sin(x) = -8
Now, to find the value of x, take the inverse sine (also known as arcsine) of both sides. This will cancel out the sine function and leave us with just x: x = arcsin(-8)
However, there's an issue here. The value of arcsin is only defined in the range [-π/2, π/2], which means it can only output values between -π/2 and π/2.
But in the equation sin(x)/8 = -1, the left-hand side (sin(x)/8) will always have an absolute value less than or equal to 1. Since the right-hand side is -1, the equation has no solutions.
In other words, there is no real value of x that satisfies the equation sin(x)/8 = -1.
If you had a typo or meant a different equation, please let me know, and I'd be happy to help you with that.


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