Question

Решить неравенство log3•(x+1)≥2​

Answer 1

Ответ:

x≥8

Пошаговое объяснение:

log₃(x+1)≥2       ОДЗ: x+1>0     x>-1

log₃(x+1)≥log₃9    3>1

x+1≥9     x≥8

Answer 2

To solve the inequality $\log_3(x + 1) \geq 2$, we need to find the values of $x$ that satisfy the inequality. Here's the step-by-step solution:

Step 1: Write the inequality in exponential form using the definition of a logarithm: $3^2 \leq x + 1$

Step 2: Simplify the exponential expression: $9 \leq x + 1$

Step 3: Isolate $x$ on one side of the inequality by subtracting 1 from both sides: $x \geq 9 - 1$ $x \geq 8$

So the solution to the inequality is $x \geq 8$. This means any value of $x$ greater than or equal to 8 will satisfy the given inequality.