Question

Найдите значение выражения (y-6)(y-8)-(y+4)(10+y) при X=1/3

Answer 1

"у "это "х "просто там нету "х"

ну можешь написать и "х" без разницы

Answer 2

To find the value of the expression $(y-6)(y-8)-(y+4)(10+y)$ when $y = \frac{1}{3}$, you simply need to substitute $y$ with $\frac{1}{3}$ and perform the arithmetic. Let's do that step by step:

Step 1: Substitute $y$ with $\frac{1}{3}$: $(\frac{1}{3} - 6)(\frac{1}{3} - 8) - (\frac{1}{3} + 4)(10 + \frac{1}{3})$

Step 2: Simplify each term: $(-\frac{17}{3})(-\frac{23}{3}) - (\frac{10}{3})(\frac{31}{3})$

Step 3: Multiply the fractions and perform the subtraction: $\frac{391}{9} - \frac{310}{9}$

Step 4: Combine the fractions: $\frac{391}{9} - \frac{310}{9} = \frac{391 - 310}{9} = \frac{81}{9}$

Step 5: Simplify the fraction: $\frac{81}{9} = 9$

So, the value of the expression $(y-6)(y-8)-(y+4)(10+y)$ when $y = \frac{1}{3}$ is $9$.