Question

{(х+3)*(х-5)<х (х+9)+7, 3х-0,4<2(х+0,4)-х?​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To solve the inequalities, we'll simplify each expression step by step. Remember that the goal is to isolate the variable x on one side of the inequality.

1. $(x + 3)(x - 5) < x(x + 9) + 7$

First, expand the expressions: $x^2 - 5x + 3x - 15 < x^2 + 9x + 7$

Combine like terms: $x^2 - 2x - 15 < x^2 + 9x + 7$

Now, move all terms to one side of the inequality (subtract $x^2$ from both sides): $-2x - 15 < 9x + 7$

Next, move the variable terms (9x) to the left side and the constant terms to the right side by subtracting 9x and adding 15 to both sides: $-2x - 9x < 7 + 15$

Simplify: $-11x < 22$

Finally, divide by -11 (since we are dividing by a negative number, the inequality sign flips): $x > -2$

So the solution to the first inequality is $x > -2$.

2. $3x - 0.4 < 2(x + 0.4) - x$

First, distribute the 2 on the right side: $3x - 0.4 < 2x + 0.8 - x$

Combine like terms: $3x - 0.4 < x + 0.8$

Now, move the variable term (x) to the left side and the constant term (-0.4) to the right side by subtracting x and adding 0.4 to both sides: $3x - x < 0.8 + 0.4$

Simplify: $2x < 1.2$

Finally, divide by 2: $x < 0.6$

So the solution to the second inequality is $x < 0.6$.

In summary:

1. $x > -2$
2. $x < 0.6$