Question

32+(136-x*88)÷4=192÷3

Answer 1

32+(136-88x)÷4=64

32+138-88x=64

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4

32+4(34-22x)=64

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4

32+34-22x=64

66-22x=64

-22x=64-66

-22x=-2

x=1

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11

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Answer 2

To solve the equation, we'll follow the order of operations (PEMDAS/BODMAS):

1. Parentheses/Brackets
2. Exponents/Orders
3. Multiplication and Division (from left to right)
4. Addition and Subtraction (from left to right)

Let's solve the equation step-by-step:

Given equation: 32 + (136 - x * 88) / 4 = 192 / 3

Step 1: Solve inside the parentheses: 136 - x * 88

Step 2: Perform the division inside the parentheses: (136 - x * 88) / 4

Step 3: Add 32 to the result of the division: 32 + (136 - x * 88) / 4

Step 4: Solve 192 / 3: 192 / 3 = 64

Now, the equation becomes: 32 + (136 - x * 88) / 4 = 64

Step 5: Move 32 to the right side of the equation: (136 - x * 88) / 4 = 64 - 32 (136 - x * 88) / 4 = 32

Step 6: Multiply both sides by 4 to get rid of the division: 136 - x * 88 = 32 * 4 136 - x * 88 = 128

Step 7: Move 136 to the right side of the equation: -x * 88 = 128 - 136 -x * 88 = -8

Step 8: Divide both sides by -88 to solve for x: x = -8 / -88 x = 0.090909... (approximately)

So, the value of x that satisfies the equation is approximately 0.0909.