Question

1)3 3/4 : 1 1/8 = 2 1/3 : а 2)(3 1/3 - 2 7/9) в квадрате * (1 1/5)

Answer 1

1) 33/4*8/11=21/3:а

3*2=6

21/3:а=6

а=6*3/21

а=1,63

2) (31/3-27/9) в квадрате * 11/5

1) 31/3-27/9= 93/9-27/9=66/9

Теперь 66/9 возводим в квадрат

4356/81

2) 4356/81*11/5=118,31...

Answer 2

To solve the given expressions, let's break them down step by step:

1. $\frac{{3 \frac{3}{4}}}{{1 \frac{1}{8}}} = \frac{{15}}{{4}} : \frac{{9}}{{8}}$

To divide fractions, we invert the second fraction and multiply:

$\frac{{15}}{{4}} \times \frac{{8}}{{9}} = \frac{{15 \times 8}}{{4 \times 9}} = \frac{{120}}{{36}}$

Now, let's simplify the fraction:

$\frac{{120}}{{36}} = \frac{{10 \times 12}}{{3 \times 12}} = \frac{{10}}{{3}}$

So, $\frac{{3 \frac{3}{4}}}{{1 \frac{1}{8}}} = \frac{{10}}{{3}}$.

2. $(3 \frac{1}{3} - 2 \frac{7}{9})^2 \times 1 \frac{1}{5}$

First, let's simplify the expression inside the parentheses:

$3 \frac{1}{3} = \frac{{10}}{{3}}$ and $2 \frac{7}{9} = \frac{{25}}{{9}}$

So, $(3 \frac{1}{3} - 2 \frac{7}{9}) = \frac{{10}}{{3}} - \frac{{25}}{{9}}$

To perform subtraction with fractions, we need a common denominator:

$\frac{{10}}{{3}} - \frac{{25}}{{9}} = \frac{{30}}{{9}} - \frac{{25}}{{9}} = \frac{{30 - 25}}{{9}} = \frac{{5}}{{9}}$

Now, let's square this result:

$\left(\frac{{5}}{{9}}\right)^2 = \frac{{5 \times 5}}{{9 \times 9}} = \frac{{25}}{{81}}$

Finally, multiply by $1 \frac{1}{5} = \frac{{6}}{{5}}$:

$\frac{{25}}{{81}} \times \frac{{6}}{{5}} = \frac{{25 \times 6}}{{81 \times 5}} = \frac{{150}}{{405}}$

Now, simplify the fraction:

$\frac{{150}}{{405}} = \frac{{30 \times 5}}{{81 \times 5}} = \frac{{30}}{{81}}$

And reduce the fraction:

$\frac{{30}}{{81}} = \frac{{10 \times 3}}{{27 \times 3}} = \frac{{10}}{{27}}$