Question

A) (-2y – 5)(0,3y + 2,7) = 0​

Answer 1

Приравняем каждую скобку к нулю

$- 2y - 5 = 0 \\ - 2y = 5 \\ y = \frac{5}{ - 2} \\ y = - 2.5$

$0.3y + 2.7 = 0 \\ 0.3y = - 2.7 \\ y = \frac{ - 2.7}{0.3} \\ y = - \frac{27}{3} \\ y = - 9$

ответ : -9 ; -2.5

Answer 2

To solve the given equation, we need to find the value of 'y' that makes the expression equal to zero. Let's proceed with the calculation step by step:

A) (-2y – 5)(0.3y + 2.7) = 0

Now, we can use the zero-product property, which states that if the product of two factors is zero, then at least one of the factors must be zero. So we set each factor equal to zero and solve for 'y'.

First factor: -2y - 5 = 0

Adding 5 to both sides: -2y = 5

Dividing by -2 (to solve for 'y'): y = -5/2

Second factor: 0.3y + 2.7 = 0

Subtracting 2.7 from both sides: 0.3y = -2.7

Dividing by 0.3 (to solve for 'y'): y = -2.7 / 0.3 y = -9

So the values of 'y' that satisfy the equation and make it equal to zero are y = -5/2 and y = -9.