Question

320-(b*4+120):5=40+5

Answer 1

Ответ:

Пошаговое объяснение:

320-(б*4+120):5=45

делим первую и последнюю части на 5

64-б*4-120=9

-б*4=120+9-64=65

б=65:(-4)=-16,25

Answer 2

To solve the equation, let's first simplify the left-hand side (LHS) and then isolate the variable 'b'.

Given equation: 320 - (b * 4 + 120) : 5 = 40 + 5

Step 1: Simplify the LHS 320 - (b * 4 + 120) : 5

First, perform the operations inside the parentheses: 320 - (b * 4 + 120) = 320 - (4b + 120)

Next, divide the result by 5: (320 - (4b + 120)) / 5

Step 2: Solve the simplified equation (320 - (4b + 120)) / 5 = 40 + 5

Step 3: Isolate 'b' To isolate 'b', we need to undo the operations done to it in reverse order.

First, multiply both sides by 5 to get rid of the division: 5 * ((320 - (4b + 120)) / 5) = 5 * (40 + 5)

This simplifies to: 320 - (4b + 120) = 45

Next, move the constant term (-120) to the right side by adding it to both sides: 320 - (4b + 120) + 120 = 45 + 120

Simplify further: 320 - 4b = 165

Finally, isolate 'b' by moving the constant term (320) to the right side by subtracting it from both sides: 320 - 4b - 320 = 165 - 320

This simplifies to: -4b = -155

To get the value of 'b', divide both sides by -4: b = -155 / -4

The final answer is: b = 38.75