
5x+34=51, (2x-32)*4=21, 7x-26=5x-48


Ответы на вопрос

Ответ:
Пошаговое объяснение:
1) 5х+34=51
5х=51-34
5х=17
х=17/5=3 2/5 = 3,4
2) (2х-32)*4=21
8х-128=21
8х=21+128
8х=149
х=149/8 = 18 5/8 = 18,625
3) 7х-26=5х-48
7х-5х=48+26
2х=74
х=74/2=37



Ответ: 5x + 34=51
5x=17
x= 17/5
x=3,4
(2x-32)*4=21
8x-128=21
8x=149
5
x= 18---
8
7x-26=5x-48
2x= -22
x= -11



To solve the equations, follow these steps:
- 5x + 34 = 51
- (2x - 32) * 4 = 21
- 7x - 26 = 5x - 48
Let's solve them one by one:
- 5x + 34 = 51
To isolate x, we need to move the constant term (34) to the other side of the equation:
5x = 51 - 34 5x = 17
Now, divide both sides by 5 to solve for x:
x = 17 / 5 x = 3.4
So, the solution for the first equation is x = 3.4.
- (2x - 32) * 4 = 21
To solve this equation, first, distribute the 4 on the left side:
8x - 128 = 21
Next, move the constant term (-128) to the other side:
8x = 21 + 128 8x = 149
Finally, divide both sides by 8 to find the value of x:
x = 149 / 8 x = 18.625
The solution for the second equation is x = 18.625.
- 7x - 26 = 5x - 48
To solve this equation, we need to isolate x. Start by moving the variable terms to one side and the constant terms to the other side:
7x - 5x = -48 + 26 2x = -22
Now, divide both sides by 2 to find x:
x = -22 / 2 x = -11
So, the solution for the third equation is x = -11.
In summary:
- x = 3.4
- x = 18.625
- x = -11


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