Question

3(x+5)^2-4x^2=(2-x)(2+x)​

Answer 1

Надеюсь помогла)))))))))))))

Answer 2

To solve the given equation, let's start by expanding and simplifying both sides:

First, expand the left-hand side (LHS): 3(x+5)^2 = 3(x+5)(x+5) = 3(x^2 + 10x + 25) = 3x^2 + 30x + 75

Next, simplify the right-hand side (RHS): (2-x)(2+x) = 22 + 2x - x2 - xx = 4 + 2x - 2x - x^2 = 4 - x^2

Now, the equation becomes: 3x^2 + 30x + 75 - 4x^2 = 4 - x^2

Combine like terms on the left-hand side: (3x^2 - 4x^2) + 30x + 75 = 4 - x^2

Simplify further: -x^2 + 30x + 75 = 4 - x^2

Since the x^2 terms on both sides cancel out, we are left with a linear equation:

30x + 75 = 4

Now, isolate the x variable on one side of the equation:

30x = 4 - 75 30x = -71

Finally, divide both sides by 30 to find the value of x:

x = -71/30

So, the solution to the equation is: x = -71/30