Question

Сократите дробь: x^2-4x+3/ (x-3)^2

Answer 1

$\frac{x^{2}-4x+3 }{(x-3)^{2} }$=$\frac{(x-3)(x-1)}{(x-3)(x+3)}$=$x-1$

Answer 2

To simplify the given expression, first factorize the numerator and denominator:

Numerator: x^2 - 4x + 3 = (x - 3)(x - 1) Denominator: (x - 3)^2

Now, you can cancel out the common factor of (x - 3) from the numerator and denominator:

(x^2 - 4x + 3) / (x - 3)^2 = [(x - 3)(x - 1)] / (x - 3)^2

Since there is still a common factor of (x - 3) in the numerator and denominator, you can simplify further by canceling it out:

[(x - 3)(x - 1)] / (x - 3)^2 = (x - 1) / (x - 3)

So the simplified expression is (x - 1) / (x - 3).