Question

Сократить дробь x^2-3x+2/x2-5x+6

Answer 1

Если приравнять к нулю числитель, то корнями по теореме, обратной теореме Виета, будут числа 1 и 2, а корнями знаменателя будут 2 и 3

Разложим числитель и знаменатель на множители и сократим.

(х²-3х+2)/(х²-5х+6)=((х-1)(х-2))/((х-2)(х-3)=(х-1)/(х-3)

Answer 2

To simplify the fraction (x^2 - 3x + 2) / (x^2 - 5x + 6), we first factor the numerator and denominator and then cancel out any common factors.

Factorizing the numerator: x^2 - 3x + 2 can be factored as (x - 2)(x - 1).

Factorizing the denominator: x^2 - 5x + 6 can be factored as (x - 2)(x - 3).

Now, the fraction becomes:

((x - 2)(x - 1)) / ((x - 2)(x - 3)).

Since (x - 2) appears in both the numerator and the denominator, it can be canceled out, leaving us with:

(x - 1) / (x - 3).

Thus, the simplified form of the fraction is (x - 1) / (x - 3).