Question

(0,6)^5+3x=125/27;​

Answer 1

Пошаговое объяснение:

$(\frac{3}{5})^{5} + 3x = (\frac{5}{3})^{3}\\\\\\3x = (\frac{5}{3})^{3} * (\frac{5}{3})^{5} =( \frac{5}{3})^{8} \\\\x = \frac{5^{8}}{3^{9}}$

Answer 2

Ответ:

x=80/81

Пошаговое объяснение:

(0,6)^5+3x=125/27

(6/10)^5+3x=(5/3)³

3x=(5/3)³-(3/5)^5

3x=(5/3)³-(3/5^-5

3x=(5/3)³ [1-(5/3)^(-²)]

3x=(5/3)³ (1-(3/5)²)

3x=(5/3)³(1-9/25)

3x=(5/3)³[(25-9)/25)]

3x=(5/3)³(16/25)

3x=(5/3)³ *(4/5)²

3x=5³/3³  *  4²/5²

3x=5*4² /3³ // : (3)

X=5*4² /3³*3  

X=5*4²/3^4

X=15*16/81=80/81

Answer 3

It appears that you have an equation that you want to solve for the value of "x." The equation is:

(0, 6)^5 + 3x = 125/27

However, the equation seems to be written in an unusual format, and it is not clear what the expression (0, 6)^5 represents. If you could provide more context or clarify the equation, I would be happy to assist you in solving for "x."