Question

Х+7/33-19/44=1 2/11​

Answer 1

Пошаговое объяснение:

$\tt\displaystyle x+\frac{7}{33}-\frac{19}{44}=1\frac{2}{11}\\\\\\x+\frac{7}{33}-\frac{19}{44}=\frac{13}{11}\\\\\\x=\frac{13}{11}-\frac{7}{33}+\frac{19}{44}\\\\\\x=\frac{13*12}{132}-\frac{7*4}{132}+\frac{19*3}{132}\\\\\\x=\frac{156}{132}-\frac{28}{132}+\frac{57}{132}\\\\\\x=\frac{156-28+57}{132}\\\\\\x=\frac{185}{132}=1\frac{53}{132}$

Answer 2

To solve the equation, let's find a common denominator for the fractions on the left side. The common denominator for 33 and 44 is 1452 (LCM of 33 and 44).

The equation can be rewritten with the common denominator as follows:

(1452 * Х + 7 * 44 - 19 * 33) / 1452 = 1 2/11

Now, let's solve the numerator:

(1452 * Х + 308 - 627) / 1452 = 1 2/11

Combine like terms:

(1452 * Х - 319) / 1452 = 1 2/11

Next, let's convert 1 2/11 to an improper fraction:

1 2/11 = (11 + 2) / 11 = 13 / 11

The equation becomes:

(1452 * Х - 319) / 1452 = 13 / 11

To isolate Х, we can cross-multiply:

11 * (1452 * Х - 319) = 1452 * 13

Expand the equation:

15972 * Х - 11 * 319 = 18876

Now, solve for Х:

15972 * Х = 18876 + 11 * 319

15972 * Х = 18876 + 3509

15972 * Х = 22385

Х = 22385 / 15972

Now, let's simplify the fraction:

Х = 1 3009 / 15972

Therefore, the value of Х that satisfies the equation is approximately 1.2044.