Question

(3∫5+425∫1000-1∫200)÷1∫10+6 3∫4+5 1∫2-1∫20=

Answer 1

$1) \frac{3}{5} + \frac{425}{1000} = \frac{600}{1000 } + \frac{425}{1000} = \frac{1025}{1000}$

$2) \frac{1025}{1000} - \frac{1}{200} = \frac{1025}{1000} - \frac{5}{1000} = \frac{1020}{1000}$

$3) \frac{1020}{1000} \div \frac{1}{10} = \frac{1020}{1000} \times \frac{10}{1} = \frac{1020 \times 10}{1000 \times 1} = \frac{1020}{100} = 10 \frac{2}{10}$

$4)10 \frac{2}{10} + 6 \frac{3}{4} = 16 \frac{8 + 30}{40} = 16 \frac{38}{40} = 16 \frac{19}{20}$

$5)16 \frac{19}{20} + 5 \frac{1}{2} = 21 \frac{19 + 10}{20} = 21 \frac{29}{20} = 22 \frac{9}{20}$

$6)22 \frac{9}{20} - \frac{1}{20} = 22 \frac{8}{20} = 22 \frac{4}{10 }$

Answer 2

To solve the given expression, let's break it down step by step:

Step 1: Evaluate the integrals. Using the integral notation, we need to compute the definite integrals within the expression.

∫5 = [5x] evaluated from x = 3 to x = 5 = 5(5) - 5(3) = 25 - 15 = 10

∫1000-1 = [x] evaluated from x = 425 to x = 1000 = 1000 - 425 = 575

∫200 = [200x] evaluated from x = 1 to x = 2 = 200(2) - 200(1) = 400 - 200 = 200

∫10+6 = [16x] evaluated from x = 3 to x = 4 = 16(4) - 16(3) = 64 - 48 = 16

∫5 = [5x] evaluated from x = 1 to x = 2 = 5(2) - 5(1) = 10 - 5 = 5

∫20 = [20x] evaluated from x = 1 to x = 20 = 20(20) - 20(1) = 400 - 20 = 380

Step 2: Perform the arithmetic operations. Now that we have the values of the integrals, we can substitute them back into the original expression and perform the calculations.

(3∫5 + 425∫1000-1∫200) ÷ 1∫10 + 6 3∫4 + 5 1∫2 - 1∫20

= (3 * 10 + 425 * 575 - 200) ÷ (16 + 6 * 5 + 5 * 380)

= (30 + 245375 - 200) ÷ (16 + 30 + 1900)

= 245205 ÷ 1946

≈ 126.07

Therefore, the value of the given expression is approximately 126.07.