Question

Дано : ABC - равносторонний AB=BC , AB=2AC P abc =30 см Найти :P adc

Answer 1

Ответ:

т.к. АВ=ВС, обозначим АВ ЧЕРЕЗ х, ВС тоже через х, а АС - 2х

т.к. АDC равносторонний и из большого треугольника нам ясно, что АС =2х, то остальные стороны тоже равны 2х.

Составляем уравнение:

х+х+2х=30 - Периметр большого треугольника.

4х=30

х=7,5

АВ = 7,5

ВС = 7,5

АС = 15, т.к. АС - 2х (2*7,5=15)

Этим уравнением нашли стороны большого треугольника.

2.

т.к. стороны маленького треугольника равны 2х, то получается 2*7,5 + 2*7,5 + 2*7,5 = 15+15+15=45 

Пошаговое объяснение:

Answer 2

To find the perimeter of triangle ADC (PADC), we need to know the lengths of its sides.

Given that triangle ABC is equilateral with AB = BC and AB = 2AC, we can use the properties of equilateral triangles to find the length of AC.

Let's assume AC = x. Since AB = 2AC, we have AB = 2x.

In an equilateral triangle, all three sides are equal. Therefore, we have:

AB = BC = 2x

Now, we know that the perimeter of triangle ABC is Pabc = AB + BC + AC = 30 cm.

Substituting the values, we get:

2x + 2x + x = 30

5x = 30

x = 6

Now that we have found the length of AC, we can find the length of AB and BC:

AB = 2x = 2 * 6 = 12 cm BC = 2x = 2 * 6 = 12 cm

Now, to find the perimeter of triangle ADC (PADC), we need to know the length of AD. Unfortunately, the given information doesn't provide any direct relationship between triangle ABC and triangle ADC.

Without additional information, we cannot determine the value of PADC.