Question

C=3y^2+4y+4 D=−7y^2+3y−6 D−C=

Answer 1

$- 10 {y}^{2} - y - 10$

Answer 2

C = 3у² + 4y + 4

D = −7y² + 3y − 6

D − C = −7y² + 3y − 6 - (3у² + 4y + 4) =
= −7y² + 3y − 6 - 3у² - 4y - 4 =
= −10y² - y − 10

Answer 3

To find the value of D−C, we need to subtract the expression for C from the expression for D.

Given: C = 3y^2 + 4y + 4 D = −7y^2 + 3y − 6

D−C = (−7y^2 + 3y − 6) - (3y^2 + 4y + 4)

Now, let's perform the subtraction term by term:

D−C = −7y^2 + 3y − 6 - 3y^2 - 4y - 4

To combine like terms, let's group the terms with the same power of y:

D−C = (−7y^2 - 3y^2) + (3y - 4y) − (6 + 4)

Now, simplify each group:

D−C = -10y^2 - y - 10

So, the expression for D−C is -10y^2 - y - 10.