Question

1. x(x-2)=9-2x 2. 2(t в квадрате + 5)=10 3. 0.1(3t в квадрате - 13)=-1 4. 5t(t-5)+2=2+5t 5. u-2(u в квадрате + u-1)=2

Answer 1

Ответ:

Пошаговое объяснение:

Если верно записала примеры, то см. ниже

Answer 2

1. Let's solve the equation x(x - 2) = 9 - 2x:

Expanding the equation: x^2 - 2x = 9 - 2x

Bringing all terms to one side: x^2 - 2x + 2x = 9 - 2x + 2x

Simplifying: x^2 = 9

Taking the square root of both sides: x = ±√9

x can have two possible values: x = 3 or x = -3

2. Let's solve the equation 2(t^2 + 5) = 10:

Expanding the equation: 2t^2 + 10 = 10

Bringing all terms to one side: 2t^2 + 10 - 10 = 10 - 10

Simplifying: 2t^2 = 0

Dividing both sides by 2: t^2 = 0/2

t^2 = 0

Taking the square root of both sides: t = ±√0

t can have only one possible value: t = 0

3. Let's solve the equation 0.1(3t^2 - 13) = -1:

Distributing 0.1 to the terms inside the parentheses: 0.3t^2 - 1.3 = -1

Adding 1.3 to both sides: 0.3t^2 - 1.3 + 1.3 = -1 + 1.3

Simplifying: 0.3t^2 = 0.3

Dividing both sides by 0.3: t^2 = 0.3/0.3

t^2 = 1

Taking the square root of both sides: t = ±√1

t can have two possible values: t = 1 or t = -1

4. Let's solve the equation 5t(t - 5) + 2 = 2 + 5t:

Expanding the equation: 5t^2 - 25t + 2 = 2 + 5t

Bringing all terms to one side: 5t^2 - 25t + 2 - 2 - 5t = 2 + 5t - 2 - 5t

Simplifying: 5t^2 - 30t = 0

Factoring out common terms: t(5t - 30) = 0

Setting each factor to zero: t = 0 or 5t - 30 = 0

If 5t - 30 = 0: 5t = 30 t = 30/5 t = 6

So, the solutions are t = 0 and t = 6.

5. Let's solve the equation u - 2(u^2 + u - 1) = 2:

Expanding the equation: u - 2u^2 - 2u + 2 = 2

Bringing all terms to one side: -2u^2 - 2u + 2 - 2 = 2 - 2

Simplifying: -2u^2 - 2u = 0

Factoring out common terms: -2u(u + 1) = 0

Setting each factor to zero: -2u = 0 or u + 1 = 0

If -2u = 0: u = 0/(-2) u = 0

If u + 1 = 0: u = -1

So, the solutions are u = 0 and u = -1.