Question

‎√6*11 ----------- ‎√2*33

Answer 1

Ответ:

$\frac{\sqrt{6}*11}{\sqrt{2}*33}=\frac{\sqrt{2}*\sqrt{3}}{\sqrt{2}*3}=\frac{\sqrt{3}}{3}=\frac{1}{\sqrt{3}}$

Пошаговое объяснение:

Answer 2

To simplify the expression, we can start by simplifying the square roots:

√6 can be written as √(2 * 3), which simplifies to √2 * √3. √2 * 33 remains the same.

Now let's substitute these values back into the expression:

(√2 * √3) * 11 / (√2 * 33)

Since √2/√2 = 1, we can cancel out the square roots:

(√3 * 11) / 33

Now we can simplify the fraction by dividing the numerator and denominator by 11:

√3 / 3

So the simplified expression is √3 / 3.