Question

5у*2-6у+1=0 3х-7-4=0

Answer 1

5у · 2 - 6у + 1 = 0

10у - 6у = - 1

4у = - 1

у = - 1 : 4

у = - 1/4

у = - 0,25

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Проверка: 5 · (-0,25) · 2 - 6 · (-0,25) + 1 = 0

                   - 2,5 + 1,5 + 1 = 0 - верно

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3х - 7 - 4 = 0

3х = 7 + 4

3х = 11

х = 11 : 3

х = 11/3

х = 3 целых 2/3

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Проверка:

3 · 11/3 - 7 - 4 = 0

11 - 7 - 4 = 0 - верно

                     

Answer 2

To solve the equations you've provided, let's take them one by one:

1. 5у*2 - 6у + 1 = 0

This is a quadratic equation in terms of "у." We can solve it by applying the quadratic formula:

The quadratic formula is given by: у = (-b ± √(b^2 - 4ac)) / (2a)

For the given equation, the coefficients are: a = 5 b = -6 c = 1

Substituting these values into the quadratic formula:

у = (-(-6) ± √((-6)^2 - 4 * 5 * 1)) / (2 * 5) = (6 ± √(36 - 20)) / 10 = (6 ± √16) / 10 = (6 ± 4) / 10

So we have two possible solutions for у: у1 = (6 + 4) / 10 = 10 / 10 = 1 у2 = (6 - 4) / 10 = 2 / 10 = 0.2

Therefore, the solutions to the equation 5у*2 - 6у + 1 = 0 are у = 1 and у = 0.2.

2. 3х - 7 - 4 = 0

Simplifying the equation, we have: 3х - 11 = 0

To isolate х, we can add 11 to both sides of the equation: 3х = 11

Dividing both sides by 3: х = 11 / 3

Therefore, the solution to the equation 3х - 7 - 4 = 0 is х = 11/3.