Question

1) x + 2 = -x + 14;2) 2x - 3 = x + 1; решить уровнение​

Answer 1

Ответ:

х переносишь в одну часть уравнения, а остальные в другую. Когда переносишь числа знак меняется на противоположный

Answer 2

х + 2 = -х+14

-х= 14-2

х= -12

Ответ: -12

2х-3=х+1

х= 3+1

х=4

Ответ: х=4

Как я поняла.

Answer 3

To solve each equation, we'll isolate the variable "x" on one side of the equation. Let's solve them one by one:

1. x + 2 = -x + 14

Step 1: Combine like terms by moving "x" terms to one side and constant terms to the other side. Add "x" to both sides: x + x + 2 = -x + x + 14 2x + 2 = 14

Step 2: Move the constant term to the other side by subtracting 2 from both sides: 2x + 2 - 2 = 14 - 2 2x = 12

Step 3: Isolate "x" by dividing both sides by 2: 2x / 2 = 12 / 2 x = 6

So, the solution for the first equation is x = 6.

2. 2x - 3 = x + 1

Step 1: Combine like terms by moving "x" terms to one side and constant terms to the other side. Subtract "x" from both sides: 2x - x - 3 = x - x + 1 x - 3 = 1

Step 2: Move the constant term to the other side by adding 3 to both sides: x - 3 + 3 = 1 + 3 x = 4

So, the solution for the second equation is x = 4.

Therefore, the solutions to the given equations are:

1. x = 6
2. x = 4