Question

Cos510°-sin1200°-tg1050°​

Answer 1

Ответ:

cos510°=cos(150°+360°)=cos150°=

= - (√3/2), тогда по этому-же принципу вычисляем все остальные и затем:

сos510°-sin1200°-tg1050°=(-√3/2)-(√3/2)-(-√3/3)=(-√3/2)-(√3/2)+(√3/3)=

= ( - 2√3/3)

Answer 2

To calculate the value of the expression cos(510°) - sin(1200°) - tan(1050°), let's break it down step by step:

1. Evaluating cos(510°): We know that the cosine function has a period of 360°, which means we can subtract multiples of 360° to find an equivalent angle within the first revolution. 510° - 360° = 150° The cosine of 150° is -0.866.

2. Evaluating sin(1200°): Similar to the cosine function, the sine function has a period of 360°. We can subtract multiples of 360° to find an equivalent angle. 1200° - 360° × 3 = 1200° - 1080° = 120° The sine of 120° is √3/2 ≈ 0.866.

3. Evaluating tan(1050°): The tangent function also has a period of 360°. Subtracting multiples of 360° gives us an equivalent angle. 1050° - 360° × 2 = 1050° - 720° = 330° The tangent of 330° is √3 ≈ 1.732.

Now, we substitute these values back into the expression: cos(510°) - sin(1200°) - tan(1050°) = -0.866 - 0.866 - 1.732 = -0.866 - 0.866 - 1.732 = -0.866 - 1.732 = -2.598

Therefore, cos(510°) - sin(1200°) - tan(1050°) is approximately equal to -2.598.