Question

4) a3- 27+a2 – 3a; Сколько будет?

Answer 1

A³-27+a²-3a=(а-3)(а²+3а+9)+а(а-3)=(а-3)(а²+4а+9)

надеюсь решила так!И помогла...Если нет извини

Answer 2

$\displaystyle \tt a^3-27+a^2-3a=(a-3)(a^2+3a+9)+a(a-3)=\\\\ \displaystyle \tt =(a-3)(a^2+3a+9+a)=\bold{(a-3)(a^2+4a+9)}$

Answer 3

To find the value of the expression, you need to substitute a specific value for 'a.' Since the value of 'a' is not provided, I cannot give you a numerical answer. However, I can help you simplify the expression.

The expression is: a^3 - 27 + a^2 - 3a

To simplify it, combine like terms: a^3 + a^2 - 3a - 27

Without a specific value for 'a,' this is the simplest form of the expression. If you provide a value for 'a,' I can help you calculate the result.