Question

2(х-2)(х+2)=(х-4)(х+4)+(х-3)(х+3)+х​

Answer 1

Ответ:

2(x²-4)=(x²-16)+(x²-9)+x

2x²-8=x²-16+x²-9+x

2x²-8=2x²-25+x

-8=-25+x

-x=-25+8

-x=-17

X=17

Answer 2

Ответ -х=-17
Х=17
Всё.

Answer 3

Let's simplify the given expression step by step:

1. Expand both sides of the equation:

Left-hand side (LHS): 2(x - 2)(x + 2) = 2(x^2 + 2x - 2x - 4) = 2(x^2 - 4)

Right-hand side (RHS): (x - 4)(x + 4) + (x - 3)(x + 3) + x = (x^2 + 4x - 4x - 16) + (x^2 + 3x - 3x - 9) + x = x^2 - 25 + x

2. Now, our equation becomes:

2(x^2 - 4) = x^2 - 25 + x

3. Distribute 2 on the left-hand side:

2x^2 - 8 = x^2 - 25 + x

4. Move all terms to one side of the equation:

2x^2 - x^2 - x - 8 + 25 = 0

5. Simplify:

x^2 - x + 17 = 0

This quadratic equation is not factorable easily, so we can use the quadratic formula to find its roots:

The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

where a = 1, b = -1, and c = 17.

6. Calculate the discriminant (Δ):

Δ = b^2 - 4ac Δ = (-1)^2 - 4 * 1 * 17 Δ = 1 - 68 Δ = -67

Since the discriminant is negative (Δ < 0), the quadratic equation has two complex roots.

7. Calculate the roots using the quadratic formula:

x = [ -(-1) ± √(-67) ] / 2*1 x = [ 1 ± √67i ] / 2

So, the two complex roots of the equation are:

x = (1 + √67i) / 2 and x = (1 - √67i) / 2

Note: The original equation provided seems to contain a mistake or might not be complete. If you have any additional information or corrections, please let me know, and I'll be happy to assist further.